Can you count suckas

[ragerayden]

a + (-c) = b + (+c)
a + ci^2 = b + c
b - a=c(1 + i^2)
(b - a)/(1 + i^2)=c
c = Cookie = Harios
Harios = (b - a)/(1 + i^2)
b = Beast
a = Anarchy
i = Imaginary

Harios = (Beast - Anarchy)/(Imaginary^2 + One)

lim Imaginary = infinity
Thus considering Beast is definite & Anarchy is broken,
lim Harios = 0

Zomg Harios doesn't exist it is a producct of your imagination & your too long AO sessions!!

[Avari]

If you really want to draw mathematics into it, you should probably use discreete math (aka. logic) and not algebraic math

... so... err... no one here knows binary math ?

Too late, scored that point alrdy

[CriticalDmg]

I'll go with modular arithmetics then ! (mod 2 in this case)

[Micandy]

Whoever brings this around to group theory with abelian groups and comes up with a good conclusion gets a cookie. I tried and failed :/

[Eskarin]

Man!

[Solsssss]

a+b=d

[NoGoal]

a+b=d

d = Anarchy Online is Death, Death!.

Here's the tricky one: db = f * i

[Solsssss]

e=mcPeenor